Lecture 29: Shahs
published: May 21, 2010, recorded: September 2007, views: 2432
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So it said this: it said the Fourier transform of F of AX – all right, so you change the variables X by a matrix A, a nonsingular matrix A – is one over the determinate of A times the Fourier transform of F evaluated at A inverse transpose at the frequency variable C. Okay? It’s a very interesting formula. We derived it last time, and it’s complicated. It’s more complicated than the one-dimensional stretch case, but it includes the one-dimensional stretch case, but what you don’t see in one dimensions is this new phenomenon as I say that reciprocal somehow means inverse transpose. ...
See the whole transcript at The Fourier Transform and its Applications - Lecture 29
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